Bài 13:
\(a,ĐK:x\ne\pm1\\ b,B=\dfrac{x^2+2x+1+6-x^2-2x+3}{2\left(x-1\right)\left(x+1\right)}\cdot\dfrac{4\left(x-1\right)\left(x+1\right)}{5}\\ B=\dfrac{10\cdot2}{5}=4\left(đpcm\right)\)
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