Question

giúp hộ câu a), b), c) e)

Answer 1

\(a,=\sqrt{\left(3+2\sqrt{2}\right)^2}+\sqrt{\left(3-2\sqrt{2}\right)^2}=3+2\sqrt{2}+3-2\sqrt{2}=6\\ b,=\sqrt{\left(5-\sqrt{2}\right)^2}+\sqrt{\left(4-\sqrt{2}\right)^2}=5-\sqrt{2}+4-\sqrt{2}=9-2\sqrt{2}\\ c,=\sqrt{8\left(3-\sqrt{5}\right)}=\sqrt{24-8\sqrt{5}}=\sqrt{\left(2\sqrt{5}-4\right)^2}=2\sqrt{5}-4\\ e,=\dfrac{\sqrt{5}\left(\sqrt{3}-1\right)}{\sqrt{3}-1}+\dfrac{\left(5-2\sqrt{5}\right)\left(2\sqrt{5}+4\right)}{4}\\ =\sqrt{5}+\dfrac{10\sqrt{5}+20-20-8\sqrt{5}}{4}\\ =\sqrt{5}+\dfrac{2\sqrt{5}}{4}=\sqrt{5}+\dfrac{\sqrt{5}}{2}=\dfrac{3\sqrt{5}}{2}\)