a: =>25-x=15
=>x=10
b: \(=\dfrac{51}{102}\cdot\dfrac{81}{54}\cdot\dfrac{2}{5}=\dfrac{1}{2}\cdot\dfrac{2}{5}\cdot\dfrac{3}{2}=\dfrac{3}{10}\)
`a) (25-x)/40 = 3/8`
`=> (25-x)/40=(3xx5)/(8xx5)`
`=> (25-x)/40 = 15/40`
`=> 25-x=15`
`=> x=25-15`
`=> x=10`
Vậy `x=10`
`b) (81xx51xx14)/(102xx34xx35)`
`= 51/102 xx81/54xx2/5=1/2xx2/5xx3/2`
`=(1xx2xx3)/(2xx5xx2) `
`= 6/20`
`= 3/10`