Question

giúp em với

Answer 1

a: ĐKXĐ: x<>8/3

b: Khi x=-1 thì \(A=\dfrac{4\cdot\left(-1\right)}{-3-8}=\dfrac{-4}{-11}=\dfrac{4}{11}\)

Answer 2

\(\text{a)ĐKXĐ:}3x-8\ne0\)

\(\Rightarrow3x\ne8\)

\(\Rightarrow x\ne\dfrac{8}{3}\)

\(\text{b)x=-1}\)

\(\Rightarrow A=\dfrac{4.\left(-1\right)}{3.\left(-1\right)-8}=\dfrac{4}{11}\)