Bài 6:
a: Ta có: \(E=\dfrac{1}{\sqrt{x}+1}:\left(\dfrac{1}{\sqrt{x}}+\dfrac{\sqrt{x}}{\sqrt{x}+1}\right)\)
\(=\dfrac{1}{\sqrt{x}+1}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{x+\sqrt{x}+1}\)
\(=\dfrac{\sqrt{x}}{x+\sqrt{x}+1}\)
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