10
a)
\(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{2}\right)^{10}\)
\(\Leftrightarrow\dfrac{1}{16^x}=\dfrac{1}{2^{10}}\)
\(\Leftrightarrow16^x=2^{10}\)
\(\Leftrightarrow\left(2^4\right)^x=2^{10}\)
\(\Leftrightarrow2^{4x}=2^{10}\)
\(\Leftrightarrow4x=10\)
\(\Leftrightarrow x=\dfrac{10}{4}\)
b)
\(\left(-\dfrac{8}{13}\right)^x=\dfrac{64}{169}\)
\(\Leftrightarrow\left(-\dfrac{8}{13}\right)^x=\left(-\dfrac{8}{13}\right)^2\)
\(\Leftrightarrow x=2\)
c)
\(\left(\dfrac{1}{64}\right)^x=\left(-\dfrac{1}{8}\right)^{14}\)
\(\Leftrightarrow\left(\dfrac{1}{8}\right)^{2x}=\left(\dfrac{1}{8}\right)^{14}\)
\(\Leftrightarrow2x=14\)
\(\Leftrightarrow x=7\)
d)
\(\left(-\dfrac{2}{3}\right)^x=-\dfrac{8}{27}\)
\(\Leftrightarrow\left(-\dfrac{2}{3}\right)^x=\left(-\dfrac{2}{3}\right)^3\)
\(\Leftrightarrow x=3\)
e)
\(\left(\dfrac{4}{9}\right)^{x+1}=\left(\dfrac{8}{27}\right)^6\)
\(\Leftrightarrow\left(\dfrac{2}{3}\right)^{2\left(x+1\right)}=\left(\dfrac{2}{3}\right)^{18}\)
\(\Leftrightarrow2\left(x+1\right)=18\)
\(\Leftrightarrow x+1=9\)
\(\Leftrightarrow x=8\)
f)
\(\left(\dfrac{1}{16}\right)^{x+2}=\left(\dfrac{1}{32}\right)^6\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4\left(x+2\right)}=\left(\dfrac{1}{2}\right)^{30}\)
\(\Leftrightarrow4\left(x+2\right)=30\)
\(\Leftrightarrow x+2=\dfrac{15}{2}\)
\(\Leftrightarrow x=\dfrac{11}{2}\)
MNG GIÚP EM BÀI 2 VỚI Ạ EM CẢM ƠN MNG NHIỀU Ạ
giúp em vài bài này với em đang cần gấp ạ em cảm ơn mn rất nhiều ạ
