Question

giúp e vứi

Answer 1

`c) x: 3/7 = 2/5 + 3/4`

`=> x: 3/7 = 23/20`

`=> x=23/20 xx 3/7`

`=>x=69/140`

`=>` Vậy `x=69/140`

`d) 19/20 - x =8/5 - 3/4`

`=> 19/20 - x=17/20`

`=>x=19/20 - 17/20`

`=>x=1/10`

`=>` Vậy `x=1/10`

Answer 2

\(c,x:\dfrac{3}{7}=\dfrac{8+15}{20}\\ \Rightarrow x:\dfrac{3}{7}=\dfrac{23}{20}\\ \Rightarrow x=\dfrac{23}{20}\times\dfrac{3}{7}\\ \Rightarrow x=\dfrac{69}{140}\\ ----------\\ d,\dfrac{19}{20}-x=\dfrac{32-15}{20}\\ \Rightarrow\dfrac{19}{20}-x=\dfrac{17}{20}\\ x-\dfrac{19}{20}-\dfrac{17}{20}=\dfrac{2}{20}=\dfrac{1}{10}\)

Answer 3

\(c,x:\dfrac{3}{7}=\dfrac{2}{5}+\dfrac{3}{4}\)

   \(x:\dfrac{3}{7}=\) \(\dfrac{23}{20}\)

         \(x=\dfrac{23}{20}\)x\(\dfrac{3}{7}\)

         \(x=\dfrac{69}{140}\)

\(d,\dfrac{19}{20}-x=\dfrac{8}{5}-\dfrac{3}{4}\)

   \(\dfrac{19}{20}-x=\)\(\dfrac{17}{20}\)

            \(x=\dfrac{19}{20}-\dfrac{17}{20}\)

           \(x=\dfrac{1}{10}\)