\(\lim\limits_{x\rightarrow2}\dfrac{2x-1}{x+2}=\dfrac{2.2-1}{2+2}=\dfrac{3}{4}\)
\(\lim\limits_{x\rightarrow1}\dfrac{3x^2-4x+1}{1-x}=\lim\limits_{x\rightarrow1}\dfrac{\left(1-x\right)\left(1-3x\right)}{1-x}=\lim\limits_{x\rightarrow1}\left(1-3x\right)=-2\)