Do AB song song CD nên: \(\widehat{ADC}=\widehat{BAD}\) (so le trong)
Mà \(\widehat{BAD}=20^0\)
\(\Rightarrow\widehat{ADC}=20^0\)
Do CD song song EF nên \(\widehat{CDE}=\widehat{DEF}\) (so le trong)
Mà \(\widehat{DEF}=50^0\)
\(\Rightarrow\widehat{CDE}=50^0\)
Vậy: \(\widehat{ADE}=\widehat{ADC}+\widehat{CDE}=20^0+50^0=70^0\)