Câu 5:
\(A=\left|x-1\right|+\left|x+2012\right|=\left|1-x\right|+\left|x+2012\right|\\ \ge\left|1-x+x+2012\right|=2013\\ A_{max}=2013\Leftrightarrow\left(1-x\right)\left(x+2012\right)\ge0\Leftrightarrow-2012\le x\le1\)
Đúng 2
Bình luận (0)