2:
\(\Leftrightarrow\dfrac{1}{\left(x-1\right)\left(x-2\right)}+\dfrac{1}{\left(x-2\right)\left(x-3\right)}+\dfrac{1}{\left(x-3\right)\left(x-4\right)}=\dfrac{3}{10}\)
=>\(-\dfrac{1}{\left(x-1\right)}+\dfrac{1}{\left(x-2\right)}-\dfrac{1}{\left(x-2\right)}+\dfrac{1}{\left(x-3\right)}-\dfrac{1}{x-3}+\dfrac{1}{x-4}=\dfrac{3}{10}\)
=>\(\dfrac{1}{x-4}-\dfrac{1}{x-1}=\dfrac{3}{10}\)
=>\(\dfrac{x-1-x+4}{\left(x-4\right)\left(x-1\right)}=\dfrac{3}{10}\)
=>x^2-5x+4-10=0
=>x^2-5x-6=0
=>(x-6)(x+1)=0
=>x=6;x=-1
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