Ta có : \(\sqrt{4x+5}+\sqrt{4x-3}=2\sqrt{3x-1}\)
=> \(\left(\sqrt{4x+5}+\sqrt{4x-3}\right)^2=\left(2\sqrt{3x-1}\right)^2\)
=> \(4x+5+4x-3+2\sqrt{4x+5}.\sqrt{4x-3}=4.\left(3x-1\right)\)
=>\(2\sqrt{4x+5}.\sqrt{4x-3}=12x-4-8x-2\)
=>\(2\sqrt{4x+5}.\sqrt{4x-3}=4x-6\)
=>\(\left(2\sqrt{4x+5}.\sqrt{4x-3}\right)^2=\left(4x-6\right)^2\)
=>\(4.\left(4x+5\right).\left(4x-3\right)=16x^2-48x+36\)
=>\(64x^2+32x-60=16x^2-48x+36\)
=>\(48x^2+80x-96=0\)
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