Question

giải pt

Answer 1

`(x+3)/2-(x-1)/3=(x+5)/6+1`

`<=>(3(x+3))/6-(2(x-1))/6=(x+5)/6+6/6`

`<=>3(x+3)-2(x-1)=x+5+6`

`<=>3x+9-2x+2=x+11`

`<=>x+11=x+11`

`<=>x-x=11-11`

`<=>0=0`

Điều này luôn đúng 

`=>x∈R`

Answer 2

 6 . \((\dfrac{x+3}{2} ) - 6 . (\dfrac{x-1}{3}) = 6 . (\dfrac{x+5}{6}) + 6 . 1\)

` 3 ( x+3) - 2(x-1) = x + 5 + 6 `

` 3x + 9 -2x + 2 = x + 11 `

` 3x - 2x - x = 11 - 9  - 2 `

` => x = 0 `