Question

Giải PT: \(\sqrt{2x-1}+x^2-3x+1=0\)

Answer 1

\(pt\Leftrightarrow2\left(x^2-2x+1\right)=\left(2x-1\right)-2\sqrt{2x-1}+1\)

\(\Leftrightarrow2\left(x-1\right)^2=\left(\sqrt{2x-1}-1\right)^2\)

\(\Leftrightarrow\left(x-1\right)\sqrt{2}=\sqrt{2x-1}-1\text{ }or\text{ }\left(x-1\right)\sqrt{2}=1-\sqrt{2x-1}\)

Answer 2

\(x=2-\sqrt{2}\)

\(x=1\)