\(\Leftrightarrow\left(x-2\right)\left(x-1\right)=\left(x+3\right)\left(x+1\right)\)
\(\Leftrightarrow x^2+4x+3=x^2-3x+2\)
=>7x=-1
hay x=-1/7
\(\Leftrightarrow\left(x-2\right)\left(x-1\right)=\left(x+3\right)\left(x+1\right)\)
\(\Leftrightarrow x^2+4x+3=x^2-3x+2\)
=>7x=-1
hay x=-1/7
Giải các pt sau:
1)\(\dfrac{2x+1}{x^2-4}+\dfrac{2}{x+1}=\dfrac{3}{2-x}\)
2)\(\dfrac{3x+1}{1-3x}+\dfrac{3+x}{3-x}=2\)
3)\(\dfrac{8x-2}{3}=1+\dfrac{5-2x}{4}\)
4)
\(\dfrac{x}{x+1}-\dfrac{2x+3}{x}=\dfrac{-3}{x+1}-\dfrac{3}{x}\)
5)\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\)
6)\(\dfrac{2x+5}{2x}-\dfrac{x}{x+5}=0\)
giúp mình với cám ơn
Giải Pt:\(\dfrac{x+1}{2021}-\dfrac{x+2}{2020}=\dfrac{x+3}{2019}+1\)
\(\dfrac{x-1}{x-2}+\dfrac{x+3}{x-4}=\dfrac{2}{-x^2+6x-8}\)
Giải pt
Giải PT sau:
\(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-\dfrac{x}{4}\)
\(\dfrac{1}{x+3}+\dfrac{8}{\left(x+1\right)\left(x-3\right)}=\dfrac{2x}{x^2-2x-3}\) giải pt
Giải PT: \(\dfrac{2x-1}{3}\) - \(\dfrac{x-1}{2}\) + \(\dfrac{x+1}{6}\) = 1
$\dfrac{x+2}{3}=$ $\dfrac{x+1}{x^2-9}$
Giải pt
$a)\dfrac{x-3}{x-2}+$$\dfrac{x-2}{x-4}=-1$
Giải pt
giải pt sau
a)\(\dfrac{60}{x}=\dfrac{4}{3}+\dfrac{60-x}{x+4}\)
b)\(\dfrac{100}{x}-\dfrac{100}{x+20}=\dfrac{5}{6}\)
c)\(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{4x^2-1}\)
Helppppp