x= 0.761322463768116,
x= 0.369494467346496,
x=1.57660410301179
x= 0.761322463768116,
x= 0.369494467346496,
x=1.57660410301179
giai pt sau
\(\sqrt{3x-1}-\sqrt{x+2}.\sqrt{3x^2+7x+2}+4=4x-2\)
\(x^2-5x+3.\sqrt{2x-1}=2.\sqrt{14-2x}+5\)
\(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6\)
Giai phương trình
a) \(\sqrt{2x+3}+\sqrt{x+1}=3x+3\sqrt{2x^2+5x+3}-16\)
b) \(\sqrt{2x^2-1}+\sqrt{x^2-3x-2}=\sqrt{2x^2+2x+3}+\sqrt{x^2-x-2}\)
c)\(5x+2\sqrt{x+1}-\sqrt{1-x}=-3\)
d) \(\sqrt{2016x^2-2005}+\sqrt{2005x^2-x-2004}=\sqrt{2006x^2+2x-2003}+\sqrt{2005x^2+x-2002}\)
Giải pt: \(3\left(x+2x\sqrt{x^2+1}\right)=-3x^2-2x\sqrt{3}+3\sqrt{3}-1\)
giải pt
1) \(\sqrt{x+3}+\sqrt{3x+1}+4\sqrt{5-x}=12\)
2) \(x+4\sqrt{x+3}+2\sqrt{3-2x}=11\)
3) \(4x\sqrt{x+3}+2\sqrt{2x-1}=4x^2+3x+3\)
4) \(x^4-x^2+3x+5-2\sqrt{x+2}=0\)
Giúp e giải pt:
2x-3+\(\frac{3x-1}{\sqrt{3-2x^2}+2-x}=0\)
\(^{x^2+4x+1=\left(x+4\right)\sqrt{x^2+1}}\)
\(2\left(x-2\right)\sqrt{x-1}=3x^2+5x-4-4x\sqrt{2x-1}\)
Giải PT: \(x\sqrt{3x-2}+\sqrt{3-2x}=\sqrt{x^3+x^2+x+1}\)
hộ e vs ak
Giải các pt vô tỉ sau ( bằng phương pháp đặt ẩn phụ đưa về phương trình tích )
a) \(\sqrt{x^3+x^2+3x+3}+\sqrt{2x}=\sqrt{x^2+3}+\sqrt{2x^2+2x}\)
b) \(\sqrt{x^2-3x}+2\sqrt{x}-4\sqrt{x-3}-x+8=0\)
c) \(\left(5x^2+4x+3\right)\sqrt{x}=\left(x+3\right)\sqrt{5x^2+4x}\)
d) \(\left(x+2\right)\sqrt{3x+\frac{1}{x}}=3x^2+3\)
e)\(\left(x^2+2x+1\right)3\sqrt{x^2+\frac{3}{x}}=x^3+2x^2+5\)
giải pt:
1) \(4\sqrt{\frac{x^2}{3}+4}=1+\frac{3x}{2}+\sqrt{6x}\)
2) \(3\left(\sqrt{2x^2+1}-1\right)=x\left(1+3x+8\sqrt{2x^2+1}\right)\)
3) \(\sqrt{1+x}+\sqrt{1-x}+\frac{x^2}{4}=2\)
Giai pt
1) \(\left(x+5\right)\left(2-x\right)=3\sqrt{x^2+3x}\)
2) \(\frac{x}{x+1}-2\sqrt{\frac{x+1}{x}}-3=0\)
3) \(x^2+\sqrt{2x^2+4x+3}=6-2x\)
4) \(x^2+\sqrt{x+5}=5\)
5) \(x^3+4x-\left(2x+7\right)\sqrt{2x+3}=0\)