Question

giải phương trình:

\(16\left(5x-1\right)^2=9\left(5+3x\right)^2\)

Answer 1

\(\Leftrightarrow\left(20x-4\right)^2-\left(9x+15\right)^2=0\)

\(\Leftrightarrow\left(20x-4-9x-15\right)\left(20x-4+9x+15\right)=0\)

=>(11x-19)(29x+11)=0

=>x=19/11 hoặc x=-11/29

Answer 2

X = - \(\dfrac{11}{29}\)

Answer 3

<=> (20x-4)^2 - (15+9x)^2 =0 

<=> (11x-19)(29x+11) = 0 

<=> x = 19/11;x=-11/29

Answer 4

x = 17 thì phải 😃