\(\left(5\right)\sqrt{x+3-4\sqrt{x-1}}\sqrt{x+8+6\sqrt{x-1}}=5\)
\(\left(6\right)2x^2+3x+\sqrt{2x^2+3x+9}=33\)
\(\left(7\right)\sqrt{3x^2+6x+12}+\sqrt{5x^4-10x^2+30}=8\)
\(\left(8\right)x+y+z+8=2\sqrt{x-1}+4\sqrt{y-2}+6\sqrt{z-3}\)
a)Giải các phương trình sau bằng phương pháp đặt ẩn phụ:
1) \(x^2-3x-3=\frac{3\left(\sqrt[3]{x^3-4x^2+4}-1\right)}{1-x}\) ;2)\(1+\frac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
b) Giải các phương trình sau(không giới hạn phương pháp):
1)\(2\left(1-x\right)\sqrt{x^2+2x-1}=x^2-2x-1\) ; 2)\(\sqrt{2x+4}-2\sqrt{2-x}=\frac{12x-8}{\sqrt{9x^2+16}}\)
3)\(\frac{3x^2+3x-1}{3x+1}=\sqrt{x^2+2x-1}\) ; 4) \(\frac{2x^3+3x^2+11x-8}{3x^2+4x+1}=\sqrt{\frac{10x-8}{x+1}}\)
5)\(13x-17+4\sqrt{x+1}=6\sqrt{x-2}\left(1+2\sqrt{x+1}\right)\);
6)\(x^2+8x+2\left(x+1\right)\sqrt{x+6}=6\sqrt{x+1}\left(\sqrt{x+6}+1\right)+9\)
7)\(x^2+9x+2+4\left(x+1\right)\sqrt{x+4}=\frac{5}{2}\sqrt{x+1}\left(2+\sqrt{x+4}\right)\)
8)\(8x^2-26x-2+5\sqrt{2x^4+5x^3+2x^2+7}\)
giải phương trình sau:
a) \(4x^2+\left(8x-4\right).\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
b) \(8x^3-36x^2+\left(1-3x\right)\sqrt{3x-2}-3\sqrt{3x-2}+63x-32=0\)
c) \(2\sqrt[3]{3x-2}-3\sqrt{6-5x}+16=0\)
d) \(\sqrt[3]{x+6}-2\sqrt{x-1}=4-x^2\)
Giải phương trình:
1)\(\sqrt{9x^2-15x+9}+\sqrt{x^3+3x^2-3x+1}+x=2\)
2)\(\sqrt{3x^2-1}+\sqrt{x^2-x}-x\sqrt{x^2+1}=\frac{1}{2\sqrt{2}}\)
3)\(\sqrt{-4x^4y^2+16x^2y+9}-\sqrt{x^2y^2-2y^2}=2\left(x^2+\frac{1}{x^2}\right)\left(vớix>0\right)\)
4)\(x^3-3x^2+2\sqrt{\left(x+2\right)^3}-6x=0\)
5)\(4x^2-11x+10=\left(x+1\right)\sqrt{2x^2-6x+2}\)
Giải các phương trình :
a) \(3x^2-6x-4=4\left(x-1\right)\sqrt{3x+1}\)
b) \(\sqrt{6x-1}+\sqrt{9x^2-1}=6x-9x^2\)
c) \(3\left(\sqrt{2x-1}+\sqrt{x+3}\right)-2\sqrt{2x^2+5x-3}=3x+4\)
Giải phương trình:
a)\(\sqrt{\sqrt{5}-\sqrt{3x}}=\sqrt{8+2\sqrt{15}}\)
b)\(\sqrt{4x-20}-3\sqrt{\dfrac{x-5}{9}}=\sqrt{1-x}\)
c) \(\sqrt{4x+8}+2\sqrt{x+2}-\sqrt{9x+18}=1\)
d) \(\sqrt{x^2-6x+9}+x=11\)
e) \(\sqrt{3x^2-4x+3}=1-2x\)
f) \(\sqrt{16\left(x+1\right)}-\sqrt{9\left(x+1\right)}=4\)
g) \(\sqrt{9x+9}+\sqrt{4x+4}=\sqrt{x+1}\)
giải phương trình :
1, \(\sqrt{4-x^2}+2\sqrt[3]{x^4-4x^3+4x^2}=\left(x-1\right)^2+1-\left|x\right|\)
2, \(2x^3+9x^2-6x\left(1+2\sqrt{6x-1}\right)+2\sqrt{6x-1}+8=0\)
3, \(x^3-3x+1=\sqrt{8-3x^2}\)
4, \(\left(4x^2+x-1\right)\sqrt{x^2+x+2}=\left(4x^2+3x+5\right)\sqrt{x^2-1}\)
5, \(\sqrt[3]{3-x^3}=2x^3+x-3\)
6, \(\sqrt[3]{x^2+3x+3}+\sqrt[3]{2x^2+3x+2}=6x^2+12x+8\)
7, \(\frac{x^2+2x-8}{x^2-2x+3}=\left(x+1\right)\left(\sqrt{x+2}-2\right)\)
8, \(\frac{4x-1}{\sqrt{4x-3}}+\frac{11-2x}{\sqrt{5-x}}=\frac{15}{2}\)
9, \(x^2-4x+14+\sqrt{x+4}=2\sqrt{1+12x}+\sqrt{1+\sqrt{1+12x}}\)
\(\sqrt{10x+1}+\sqrt{3x+5}=\sqrt{9x+4}+\sqrt{2x-2}\)
\(\sqrt{2x^2+x-1}+\sqrt{3x^2+x-1}=\sqrt{x^2+4x-3}-\sqrt{x^2-3x+4}\)
\(\frac{x^2}{\left(1+\sqrt{x+1}\right)^2}>x-4\)
1\(\sqrt{5+2\sqrt{8}}-\sqrt{5-2\sqrt{8}}\) 2)\(\dfrac{\sqrt{x^2+2\sqrt{3x}+3}}{x^2-3}\) 3) \(\dfrac{\sqrt{x^2-5x+6}}{\sqrt{x-2}}\) 4)\(\dfrac{\sqrt{\left(x-4\right)^2}}{x^2-5x+4}\) 5) \(\dfrac{3x+1}{\sqrt{9x^2+6x+1}}\)