Question

Giải phương trình

Answer 1

b: \(\Leftrightarrow\dfrac{3}{4\left(x-5\right)}-\dfrac{15}{2\left(x-5\right)\left(x+5\right)}+\dfrac{7}{6\left(x+5\right)}=0\)

=>\(9\left(x+5\right)-90+12\left(x-5\right)=0\)

=>9x+45-90+12x-60=0

=>21x-105=0

=>x=5(loại)

d: =>3(2x+3)=6(2x+1)+8

=>6x+9=12x+6+8

=>12x+14=6x+9

=>6x=-5

=>x=-5/6(nhận)

g: \(\Leftrightarrow\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{x+3}=\dfrac{3}{10}\)

=>\(\dfrac{x+3-x}{x^2+3x}=\dfrac{3}{10}\)

=>x^2+3x=10

=>x=2(nhận) hoặc x=-5(nhận)