\(\Leftrightarrow\dfrac{x+5}{2x^2-5x+2}=\dfrac{2x+7-x-2}{2x^2-7x+3}\)
\(\Leftrightarrow\left(x+5\right)\left(\dfrac{1}{\left(2x-1\right)\left(x-2\right)}-\dfrac{1}{\left(x-3\right)\left(2x-1\right)}\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(x-3-x+2\right)=0\)
=>x+5=0
hay x=-5