\(\left\{{}\begin{matrix}4x-8=-2y\\y+2x=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x-8=-2\cdot\left(4-2x\right)\\y=4-2x\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x-8=-8+4x\\y+2x=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}0=0\left(\text{đúng}\right)\\y+2x=4\end{matrix}\right.\)
Vậy hệ phương trình có vô số nghiệm
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\(2x^2-3x+1=0\)
\(\Delta=\left(-3\right)^2-4\cdot2\cdot1=1>0\)
\(x_1=\dfrac{3+\sqrt{1}}{2}=2\)
\(x_2=\dfrac{3-\sqrt{1}}{2}=1\)