Question

Giải hpt \(\left\{{}\begin{matrix}2x-3y=1\\\dfrac{x}{2}+y=2\end{matrix}\right.\)

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}2x-3y=1\\\dfrac{3x}{2}+3y=6\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{7x}{2}=7\\y=2-\dfrac{x}{2}\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)