`a)x^2 - 4+x(x-2)=0`
`<=>(x-2)(x+2)+x(x-2)=0`
`<=>(x-2)[(x+2)+x]=0`
`<=>(x-2)(x+2+x)=0`
`<=>(x-2)(2x+2)=0`
`<=>x-2=0` hoặc `2x+2=0`
`<=>x=2` hoặc `x=-1`
Vậy `x=-1` hoặc `x=2`
`b)(2x+1)^2 - 4x^2=0`
`<=>[(2x+1)-2x][(2x+1)+2x]=0`
`<=>(2x+1-2x)(2x+1+2x)=0`
`<=>1(4x+1)=0`
`<=>4x+1=0`
`<=>4x=-1`
`<=>x=-1/4`
Vậy `x=-1/4`
`c)x^2 - 75x=0`
`<=>x(x-75)=0`
`<=>x=0` hoặc `x-75=0`
`<=>x=0` hoặc `x=75`
Vậy `x=0` hoặc `x=75`
a, \(x^2-4+x\left(x-2\right)=0\Leftrightarrow\left(x-2\right)\left(x+2\right)+x\left(x-2\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x+2+x\right)=0\Leftrightarrow x=2;x=-1\)
b, \(\left(2x+1\right)^2-4x^2=0\Leftrightarrow\left(2x+1\right)^2-\left(2x\right)^2=0\)
\(\Leftrightarrow\left(2x+1-2x\right)\left(2x+1+2x\right)=0\Leftrightarrow4x+1=0\Leftrightarrow x=-\dfrac{1}{4}\)
c, \(x^2-75x=0\Leftrightarrow x\left(x-75\right)=0\Leftrightarrow x=0;x=75\)