Question

giải hộ mik câu b vs ạ

 

Answer 1

a: \(B=\dfrac{x+\sqrt{x}-1-x+1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}-1}{1}\)

\(=\dfrac{\sqrt{x}}{x+\sqrt{x}+1}\)

b: \(B-\dfrac{1}{3}=\dfrac{\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{1}{3}\)

\(=\dfrac{3\sqrt{x}-x-\sqrt{x}-1}{3\left(x+\sqrt{x}+1\right)}\)

\(=\dfrac{-\left(\sqrt{x}+1\right)^2}{3\left(x+\sqrt{x}+1\right)}< 0\)

=>B<1/3