Question

giải hệ phương trình \(\left\{{}\begin{matrix}x+y=\dfrac{1}{2}\\2y+1=3\end{matrix}\right.\) với x, y ∈ Z

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{1}{2}-y\\y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{2}\\y=1\end{matrix}\right.\Leftrightarrow x,y\in\varnothing\left(x,y\in Z\right)\)