Question

Giải giúp mình với ạ mình đang cần gấp

Answer 1

a: \(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}=\dfrac{5x+4}{3}+3\)

=>\(\dfrac{7\left(4x+3\right)-5\left(6x-2\right)}{35}=\dfrac{5x+4+9}{3}\)

=>\(\dfrac{28x+21-30x+10}{35}=\dfrac{5x+13}{3}\)

=>\(\dfrac{-2x+31}{35}=\dfrac{5x+13}{3}\)

=>\(35\left(5x+13\right)=3\left(-2x+31\right)\)

=>175x+455=-6x+93

=>181x=93-455=-362

=>x=-2

b: \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)

=>\(\dfrac{5x+2-2\left(8x-1\right)}{6}=\dfrac{4x+2-25}{5}\)

=>\(\dfrac{5x+2-16x+2}{6}=\dfrac{4x-23}{5}\)

=>\(\dfrac{-11x+4}{6}=\dfrac{4x-23}{5}\)

=>5(-11x+4)=6(4x-23)

=>-55x+20=24x-138

=>-79x=-138-20=-158

=>x=2

c: \(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{x+7}{15}\)

=>\(\dfrac{3\left(2x-1\right)-5\left(x-2\right)}{15}=\dfrac{x+7}{15}\)

=>\(\dfrac{6x-3-5x+10}{15}=\dfrac{x+7}{15}\)

=>x+7=x+7

=>0x=0

=>\(x\in R\)

d: \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)

=>\(\dfrac{5x-3}{6}-\dfrac{7x-1}{4}=\dfrac{4x+2}{7}-5\)

=>\(\dfrac{2\left(5x-3\right)-3\left(7x-1\right)}{12}=\dfrac{4x+2-35}{7}\)

=>\(\dfrac{-11x-3}{12}=\dfrac{4x-33}{7}\)

=>\(12\left(4x-33\right)=7\cdot\left(-11x-3\right)\)

=>48x-396=-77x-21

=>125x=-21+396=375

=>x=3

e: \(\dfrac{x}{3}-\dfrac{2x+1}{6}=\dfrac{x}{6}-x\)

=>\(\dfrac{2x}{6}-\dfrac{2x+1}{6}=\dfrac{x}{6}-\dfrac{6x}{6}\)

=>-5x=-1

=>\(x=\dfrac{1}{5}\)

f: \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)

=>\(\dfrac{6x+3}{4}-5=\dfrac{6x-2}{5}-\dfrac{3x+2}{10}\)

=>\(\dfrac{5\left(6x+3\right)}{20}-\dfrac{100}{20}=\dfrac{4\left(6x-2\right)}{20}-\dfrac{2\left(3x+2\right)}{20}\)

=>30x+15-100=24x-8-6x-4

=>30x-85=18x-12

=>12x=-12+85=73

=>\(x=\dfrac{73}{12}\)