a) PTHH: \(Na+H_2O\rightarrow NaOH+\dfrac{1}{2}H_2\uparrow\)
b+c+d) Ta có: \(n_{Na}=\dfrac{4,6}{23}=0,2\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{NaOH}=0,2\left(mol\right)\\n_{H_2}=0,1\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_{NaOH}=0,2\cdot40=8\left(g\right)\\V_{H_2}=0,1\cdot22,4=2,24\left(l\right)\\m_{H_2}=0,1\cdot2=0,2\left(g\right)\end{matrix}\right.\)
Mặt khác: \(m_{dd\left(saup/ứ\right)}=m_{Na}+m_{H_2O}-m_{H_2}=204,4\left(g\right)\)
\(\Rightarrow C\%_{NaOH}=\dfrac{8}{204,4}\cdot100\%\approx3,91\%\)
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H2 + O2 to H2O
