d) Ta có: \(\left(\dfrac{a\sqrt{b}+b\sqrt{a}}{\sqrt{ab}}+\dfrac{2b}{\sqrt{a}-\sqrt{b}}\right)\left(\dfrac{a-b}{\sqrt{a^3}+\sqrt{b^3}+\sqrt{a^2b}+\sqrt{ab^2}}\right)\)
\(=\left(\sqrt{a}+\sqrt{b}+\dfrac{2b}{\sqrt{a}-\sqrt{b}}\right)\cdot\left(\dfrac{a-b}{a\sqrt{a}+b\sqrt{b}+a\sqrt{b}+b\sqrt{a}}\right)\)
\(=\dfrac{a-b+2b}{\sqrt{a}-\sqrt{b}}\cdot\dfrac{a-b}{\left(\sqrt{a}+\sqrt{b}\right)\left(a+b\right)}\)
\(=\dfrac{\left(a+b\right)\cdot\left(\sqrt{a}-\sqrt{b}\right)\left(\sqrt{a}+\sqrt{b}\right)}{\left(a+b\right)\left(\sqrt{a}-\sqrt{b}\right)\left(\sqrt{a}+\sqrt{b}\right)}\)
=1