Question

  giải giúp mik vs

Answer 1

a: \(P\left(x\right)=7x^3+3x^4-x^2+5x^2-6x^3-2x^4+2017-x^3\)

\(=\left(3x^4-2x^4\right)+\left(7x^3-6x^3-x^3\right)+5x^2-x^2+2017\)

\(=x^4+4x^2+2017\)

b: \(P\left(1\right)=1^4+4\cdot1^2+2017=1+4+2017=2022\)

Answer 2

Lời giải:

a. 

$P(x)=(3x^4-2x^4)+(7x^3-6x^3-x^3)+(-x^2+5x^2)+2017$

$=x^4+4x^2+2017$

b.

$P(1)=1^4+4.1^2+2017=2022$