\(g,=\dfrac{\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{2}\left(\sqrt{3}-\sqrt{2}\right)}+\dfrac{4\left(\sqrt{3}-1\right)}{2}+12-3\sqrt{3}\\ =\sqrt{3}+2\sqrt{3}-2+12-3\sqrt{3}=10\)
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