\(=\dfrac{5}{11}-\dfrac{3}{5}+\dfrac{6}{11}=1-\dfrac{3}{5}=\dfrac{5}{5}-\dfrac{3}{5}=\dfrac{2}{5}\)
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\(\dfrac{5}{11}-\dfrac{3}{5}+\dfrac{6}{11}=\left(\dfrac{5}{11}+\dfrac{6}{11}\right)-\dfrac{3}{5}=1-\dfrac{3}{5}=\dfrac{2}{5}\)
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