x=-0.5 nha bạn! Cài này là trong violympic
\(\Leftrightarrow\frac{x}{x+2}-\frac{1}{x+2}=\frac{x}{x+3}-\frac{2}{x+3}\)
\(\Rightarrow-\frac{x}{x+3}+\frac{2}{x+3}+\frac{x}{x+2}-\frac{1}{x+2}=0\)
\(\Leftrightarrow\frac{2x+1}{\left(x+2\right)\left(x+3\right)}=0\)
ta có 2x+1=0*(x+2)(x+3)
=>2x+1=0
=>2x=-1
\(x=-\frac{1}{2}\)