Question

\(\frac{3}{7×10}+\frac{3}{10×13}+......+\frac{3}{97×1001}\)

Cái cuối là 97×100 nha, cậu nào giải hộ mk cài ạ

 

Answer 1

\(\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{97.100}=\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{97}-\frac{1}{100}=\frac{1}{7}-\frac{1}{100}=\frac{93}{700}\)

Answer 2

\(\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+...+\frac{3}{97\cdot100}\)

\(=\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{97}-\frac{1}{100}=\frac{1}{7}-\frac{1}{100}=\frac{93}{700}\)

Answer 3

\(\frac{3}{7\times10}+\frac{3}{10\times13}+...+\frac{3}{97\times100}\)

\(=\frac{3}{7}-\frac{3}{10}+\frac{3}{10}-\frac{3}{13}+...+\frac{3}{97}-\frac{3}{100}\)

 \(=\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{97}-\frac{1}{100}\)

   \(=\frac{1}{7}-\frac{1}{100}\)

 \(=\frac{93}{100}\)

                     hok tốt

Answer 4

À mik quên = \(\frac{93}{700}\)nha