\(\frac{27\cdot18+27\cdot103-27\cdot120}{15\cdot33+12\cdot33}=\frac{27\left(18+103-120\right)}{33\left(15+12\right)}\)\(=\frac{27\cdot1}{33\cdot27}=\frac{1}{33}\)
\(\Leftrightarrow x-\frac{1}{3}=\left(+-\right)\frac{5}{6}\)
nếu \(x-\frac{1}{3}=\frac{5}{6}\) nếu \(x-\frac{1}{3}=-\frac{5}{6}\)
\(\Leftrightarrow x=\frac{5}{6}+\frac{1}{3}\) \(\Leftrightarrow x=-\frac{5}{6}+\frac{1}{3}\)
\(\Leftrightarrow x=\frac{7}{6}\) \(\Leftrightarrow x=-\frac{1}{2}\)
Vậy ....
nhớ k mk nha bạn , mk nhanh nhất
thanks
\(\frac{27.18+27.103-120.27}{15.33+33.12}\)
\(=\)\(\frac{27.\left(18+103-120\right)}{33.\left(15+12\right)}\)
\(=\)\(\frac{27.1}{33.27}\)
\(=\)\(\frac{1}{33}\)
\(|x-\frac{1}{3}|=\frac{5}{6}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x-\frac{1}{3}=\frac{5}{6}\\x-\frac{1}{3}=-\frac{5}{6}\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=\frac{5}{6}+\frac{1}{3}\\x=-\frac{5}{6}+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=\frac{7}{6}\\x=-\frac{1}{2}\end{cases}}\)
Vậy \(x=\frac{7}{6};-\frac{1}{2}\)
