Question

$\frac{1978 . 1979 + 1}{1979 . 1980 - 3957 }$ 

Answer 1

`= (1978.1979+1)/(1979.1980 - 3957)`

`= (1978 . 1979+1)/(1979 . (1978 + 2) - 3957)`

`= (1978 . 1979 + 1)/(1979 . 1978 + 1)`

`= 1`.

Answer 2

\(\dfrac{1978\cdot1979+1}{1979\cdot1980-3957}\\ =\dfrac{1978\cdot1979+1}{1979\cdot1980-3958+1}\\ =\dfrac{1978\cdot1979+1}{1979\cdot1980-1979\cdot2+1}\\ =\dfrac{1979\cdot1978+1}{1979\cdot\left(1980-2\right)+1}\\ =\dfrac{1979\cdot1978+1}{1979\cdot1978+1}\\ =1\)