\(\frac{25}{12}.\frac{23}{7}-\frac{25}{12}.\frac{12}{7}\)
\(=\frac{25}{12}.\left(\frac{23}{7}-\frac{12}{7}\right)\)\(\)
\(=\frac{25}{12}.\frac{11}{7}\)
\(=\frac{275}{84}\)
\(-\frac{6}{7}.\frac{7}{10}.\frac{11}{-6}.\left(-20\right)\)
\(=-\frac{3}{5}.\frac{-11}{6}.\left(-20\right)\)
\(=\frac{11}{10}.\left(-20\right)\)
\(=-22\)
Tính
\(\frac{12}{25}.\frac{23}{7}-\frac{12}{25}.\frac{12}{7}=\frac{12}{25}\left(\frac{23}{7}-\frac{12}{7}\right)\)
\(=\frac{12}{25}.\frac{11}{7}=\frac{132}{175}\)
\(-\frac{6}{11}.\frac{7}{10}.\frac{11}{-6}.\left(-20\right)\)
\(=\frac{-6.7.11.\left(-20\right)}{11.10.\left(-6\right)}=7.\left(-20\right)=-140\)
Sửa lại câu thứ 2 :vv
\(-\frac{6}{11}.\frac{7}{10}.\frac{11}{6}.\left(-20\right)=\frac{-6.7.11.\left(-20\right)}{11.10.6}=7.\left(-2\right)=-14\)
sửa câu 2
\(-\frac{6}{11}.\frac{7}{10}.\frac{-11}{6}.\left(-20\right)\)
\(=-\frac{21}{55}.\frac{-11}{6}.\left(-20\right)\)
\(=\frac{7}{10}.\left(-20\right)\)
\(=-14\)
a ,12/25 . 23/7 - 12/25 . 12/7
= 12/25 . ( 23/7 - 12/7)
= 12/25 . 11/7
= 132/175
b , -6/11 . 7/10 . 11/-6 . (-20)
= -6.7.11.(-20) / 11.10.6
= 7 . (-20)
=-140 .
Bài làm
a, \(\frac{12}{25}.\frac{23}{7}-\frac{12}{25}.\frac{12}{7}=\frac{12}{25}\left(\frac{23}{7}-\frac{12}{7}\right)=\frac{12}{25}.\frac{11}{7}=\frac{132}{175}\)
b, \(\frac{-6}{11}.\frac{7}{10}.\left(\frac{11}{-6}\right)\left(-20\right)=\frac{-6.7.11.\left(-20\right)}{11.10.\left(-6\right)}=\frac{7.\left(-20\right)}{10}=\frac{-140}{10}=-14\)
cảm ơn các bn trả lời câu hỏi của mik
thank you very much...