Question

e)(x-2).y=3 , f) (2-x).(y-4)=7 .-; nhờ love math .-.

Answer 1

:)))))

Answer 2

\(e,\left(x-2\right)y=3\)

Mà x, y∈Z⇒\(x-2\in Z,y\in Z\) và \(x-2,y\inƯ\left(3\right)\)

Ta có bảng:
 

x-2	1	3	-1	-3
y	3	1	-3	-1
x	3	5	1	-1
y	3	1	-3	-1

Vậy \(\left(x,y\right)\in\left\{\left(3;3\right);\left(5;1\right);\left(1;-3\right);\left(-1;-1\right)\right\}\)

b, \(\left(2-x\right)\left(y-4\right)=7\)

Mà x, y∈Z⇒\(2-x\in Z,y-4\in Z\) và \(2-x,y-4\inƯ\left(7\right)\)

Ta có bảng:

2-x	1	7	-1	-7
y-4	7	1	-7	-1
x	1	-5	3	9
y	11	5	-3	3

Vậy \(\left(x,y\right)\in\left\{\left(1;11\right);\left(-5;5\right);\left(3;-3\right);\left(9;3\right)\right\}\)

 

Answer 3

f )(2.x).(y-4)=7

+)2.x=7

x=7:2

x=3,5 vậy x thuộc rỗng

+)y-4=7

x=7+4

x=11