\(n_{C_2H_2}=\dfrac{2,6}{26}=0,1\left(mol\right)\\ 2C_2H_2+5O_2\rightarrow\left(t^o\right)4CO_2+2H_2O\\ a,n_{O_2}=\dfrac{5}{2}.n_{C_2H_2}=\dfrac{5}{2}.0,1=0,25\left(mol\right)\\ \Rightarrow V_{O_2\left(đktc\right)}=0,25.22,4=5,6\left(l\right)\\ b,n_{CO_2}=\dfrac{4}{2}.n_{C_2H_2}=\dfrac{4}{2}.0,1=0,2\left(mol\right)\\ \Rightarrow m_{CO_2}=0.2.44=8,8\left(g\right)\\ n_{H_2O}=n_{C_2H_2}=0,1\left(mol\right)\\ \Rightarrow m_{H_2O}=0,1.18=1,8\left(g\right)\\ \Rightarrow m_{sp}=m_{CO_2}+m_{H_2O}=8,8+1,8=10,6\left(g\right)\)
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