\(\dfrac{x+3}{-4}=\dfrac{1-x}{5}\)
\(\Rightarrow5\left(x+3\right)=-4\left(1-x\right)\)
\(\Leftrightarrow5x+15=-4+4x\)
\(\Leftrightarrow5x-4x=-4-15\)
\(\Leftrightarrow x=-19\)
Vậy \(x=-19\).
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\(\dfrac{x+3}{-4}=\dfrac{1-x}{5}\\ \Rightarrow5\left(x+3\right)=-4\left(1-x\right)\\ \Rightarrow5x+15=-4+4x\\ \Rightarrow5x+15+4-4x=0\\ \Rightarrow19+x=0\\ \Rightarrow x=-19\)
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