ĐKXĐ: \(x\ge0;x\ne1\)
\(\dfrac{x+2\sqrt{x}}{\sqrt{x}-1}=8\)
\(\Rightarrow x+2\sqrt{x}=8\sqrt{x}-8\)
\(\Leftrightarrow x-6\sqrt{x}+8=0\)
\(\Leftrightarrow\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\sqrt{x}-2=0\\\sqrt{x}-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=16\end{matrix}\right.\) (thỏa mãn)