28/31: 7/31= 4/1=4
8/9: 4/9= 2/1=2
vậy nó là 2
28/31: 7/31= 4/1=4
8/9: 4/9= 2/1=2
vậy nó là 2
\(\dfrac{8\dfrac{1}{2}}{15:\dfrac{5}{17}}\) \(\dfrac{4\dfrac{4}{5}:\dfrac{4}{17}}{3\dfrac{2}{5}}\) \(\dfrac{\dfrac{28}{29}:\dfrac{4}{29}}{\dfrac{7}{9}:\dfrac{1}{9}}\) Cứu tui
\(\dfrac{2}{5}\)*\(15\dfrac{1}{3}\)-\(\dfrac{2}{5}\)*\(10\dfrac{1}{3}\)
\(12\dfrac{5}{11}\)-(\(3\dfrac{1}{4}\)+\(2\dfrac{5}{11}\)]
\(\dfrac{34}{31}\)-\(\dfrac{19}{28}\)-\(\dfrac{3}{31}\)
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
a,\(\dfrac{1}{7}\text{x}\dfrac{2}{7}+\dfrac{1}{7}\text{x}\dfrac{5}{7}+\dfrac{6}{7}\) b,\(\dfrac{6}{11}\text{x}\dfrac{4}{9}+\dfrac{6}{11}\text{x}\dfrac{7}{9}-\dfrac{6}{11}\text{x}\dfrac{2}{9}\)
c, \(\dfrac{4}{25}\text{x}\dfrac{5}{8}\text{x}\dfrac{25}{4}\text{x}24\)
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
so sánh các hỗn số sau:
\(7\dfrac{4}{5}\) và \(9\dfrac{1}{2}\)
\(7\dfrac{1}{6}\) và \(3\dfrac{4}{5}\)
\(9\dfrac{9}{1}\) và \(5\dfrac{8}{6}\)
a) \(\dfrac{5}{7}\) + x =\(\dfrac{8}{9}\)
b)\(\dfrac{7}{9}\) : =\(\dfrac{2}{3}\)
c)\(\dfrac{3}{4}\) x x =\(\dfrac{7}{12}\)
cứu tui bài này với các thánh ui
Bài 2: (Đề1) Tính
\(4\dfrac{2}{3}+3\dfrac{2}{7}\)=..........................
\(8\dfrac{5}{9}:5\dfrac{1}{2}\) =..........................
\(6\dfrac{5}{7}:2\dfrac{1}{6}\) =..........................
\(1\dfrac{3}{4}x2\dfrac{5}{6}\) =..........................
\(5\dfrac{3}{4}-2\) =..........................
Điền dấu < ; > ; =
3\(\dfrac{1}{5}-\dfrac{8}{3}...........\dfrac{17}{5}-2\dfrac{12}{5}\)
\(\dfrac{1}{31}+\dfrac{1}{32}+\dfrac{1}{33}+....+\dfrac{1}{89}+\dfrac{1}{90}\) ..... \(\dfrac{5}{6}\)