\(\dfrac{3x+2}{3}\le\dfrac{x-4}{7}\) help em vs mn ơi
1).(4-3x)(10-5x)=0 2).(7-2x)(4+8x)=0 3).(9-7x)(11-3x)=0
4).(7-14x)(x-2)=0 5).(\(\dfrac{7}{8}\)-2x)(3x+\(\dfrac{1}{3}\))=0 6).3x-2x\(^2\)
7).5x+10x\(^2\)
\(\dfrac{3-3x}{5}\)=\(\dfrac{x-1}{2}\) help em vs mn
(1) 1>.-3x.(x2 +7x- 1/3)
2. -5x2y4(3x2y3-2x3y2-xy)
3. \(\dfrac{1}{2}\)x3y .(2x4y3-4xy-6)
4. -2x.(3x+20
5. 3x.(5-2x)
6. 2x.(2x2-4x+5)
7. 4x3y2.(-2x2y+4x4-3y2)
8.\(\dfrac{1}{2}\)x3y.( 2x4y3- 4xy -6)
1/ \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
2/ \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
3/ \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
4/ \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
5/ \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
Giải các phương trình sau:
\(e.\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
\(f.\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
\(g.\dfrac{2}{x+2}-\dfrac{2x^2+16}{x^3+8}=\dfrac{5}{x^2-2x+4}\)
\(h.\dfrac{8}{x-8}+\dfrac{11}{x-11}=\dfrac{9}{x-9}+\dfrac{10}{x-10}\)
a) 6-7x+7=-8x+12
b) \(\dfrac{\text{4x-1}}{8}\)\(\)=\(\dfrac{6-x}{2}\)-\(\dfrac{1}{4}\)
c) 2x(x-3)+7x-21+0
d) \(\dfrac{x}{x-3}\)+\(\dfrac{x-2}{x+3}\)\(\dfrac{2\left(x^2+6\right)}{x^2-9}\)
bài 2 giải các phương trình sau
b,\(\dfrac{2\left(3-7x\right)}{1+x}=\dfrac{1}{2}\) m,\(\dfrac{3x-1}{x+1}=\dfrac{2x+1}{x-1}\)
d,\(\dfrac{3x-14}{x+5}=\dfrac{2}{3}\) p,\(\dfrac{4x+7}{x-1}=\dfrac{12x+5}{3x+4}\)
f,\(\dfrac{6}{x}-1=\dfrac{2x-3}{3}\) r,\(\dfrac{1}{x+3}+\dfrac{1}{x-1}=\dfrac{10}{\left(x+3\right)\left(x-1\right)}\)
h,\(\dfrac{1}{x-2}+3=\dfrac{x-3}{2-x}\) t,\(\dfrac{3x}{x-2}-\dfrac{x}{x-5}=\dfrac{3x}{\left(x-2\right)\left(5-x\right)}\)
j,\(\dfrac{5}{3x+2}=2x-1\) u,\(\dfrac{x+3}{x+1}+\dfrac{x-2}{x}=\dfrac{2\left(x^2+x-1\right)}{x\left(x+1\right)}\)
w,\(\dfrac{5x}{2x+2}+1=-\dfrac{6}{x+1}\) s, \(\dfrac{6}{x-1}-\dfrac{4}{x-3}=\dfrac{2x}{\left(x-1\right)\left(x-3\right)}\)
ơ,\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\) v,\(\dfrac{x}{2\left(x-3\right)}+\dfrac{x}{2\left(x+1\right)}=\dfrac{2x}{\left(x+1\right)\left(x-3\right)}\)
z,\(\dfrac{1}{x-1}-\dfrac{3x^2}{x^3-1}=\dfrac{2x}{x^2+x+1}\) ư,\(\dfrac{x+2}{x-2}-\dfrac{-2}{x^2-2x}=\dfrac{1}{x}\)
o,\(x+\dfrac{1}{x}=x^2+\dfrac{1}{x^2}\) ô,\(1-\dfrac{1}{1-x}=\dfrac{x^2}{x^2-1}\) zz,\(\dfrac{12}{8+x^3}=1+\dfrac{1}{x+2}\)
Giải phương trình:
a) \(\dfrac{3x-2}{x^2-12x+20}-\dfrac{4x+3}{x^2+6x-16}=\dfrac{7x+11}{x^2-2x-80}\)
b) \(\dfrac{2x-5}{x^2+5x-36}-\dfrac{x-6}{x^2+3x-28}=\dfrac{x+8}{x^2+16x+63}\)