\(\dfrac{3\left(x+3\right)}{4}+\dfrac{1}{2}=\dfrac{5x+9}{3}-\dfrac{7x-9}{4}\)
=>\(\dfrac{3\left(x+3\right)+2}{4}=\dfrac{4\left(5x+9\right)-3\left(7x-9\right)}{12}\)
=>\(\dfrac{3x+11}{4}=\dfrac{20x+36-21x+27}{12}\)
=>\(\dfrac{3x+11}{4}=\dfrac{-x+63}{12}\)
=>3(3x+11)=-x+63
=>9x+33=-x+63
=>10x=30
=>x=3
\(\dfrac{3\left(x+3\right)}{4}+\dfrac{1}{2}=\dfrac{5x+9}{3}-\dfrac{7x-9}{4}\)
\(\Leftrightarrow9\left(x+3\right)+6=4\left(5x+9\right)-3\left(7x-9\right)\)
\(\Leftrightarrow9x+27+6=20x+36-21x+27\)
\(\Leftrightarrow9x+27+6-20x-36+21x-27=0\)
\(\Leftrightarrow10x-30=0\)
\(\Leftrightarrow10x=30\Leftrightarrow x=3\)
