\(\dfrac{3}{4}-\left(x-\dfrac{2}{3}\right)=1\dfrac{1}{2}\)
\(\Rightarrow\dfrac{3}{4}-\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{3}{4}-\dfrac{3}{2}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{3}{4}-\dfrac{6}{4}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{-3}{4}\)
\(\Rightarrow x=\dfrac{-3}{4}+\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{-9}{12}+\dfrac{8}{12}\)
\(\Rightarrow x=\dfrac{-1}{12}\)
Vậy \(x=\dfrac{-1}{12}\)