\(\dfrac{2x+5}{9}=\dfrac{7}{18}=>\dfrac{9\cdot7}{18}=2x+5\)
\(2x+5=3.5\)
\(2x=3.5-5\)
\(2x=\left(-1.5\right)\)
\(x=\left(-1.5\right):2\)
\(x=-0.75\)
=> x = -0.75
~ HT ~
\(\dfrac{2x+5}{9}=\dfrac{7}{18}=>\dfrac{9\cdot7}{18}=2x+5\)
\(2x+5=3.5\)
\(2x=3.5-5\)
\(2x=\left(-1.5\right)\)
\(x=\left(-1.5\right):2\)
\(x=-0.75\)
=> x = -0.75
~ HT ~
Tìm x:
a) -2x + \(\dfrac{5}{7}\) = - \(\dfrac{5}{15}\) - \(\dfrac{3}{24}\)
b) 9 - 5x = - \(\dfrac{6}{18}\) + \(\dfrac{2}{7}\)
\(\dfrac{2x}{18}\)-\(\dfrac{2}{3}\)=\(\dfrac{5}{9}\)
bài 1:thực hiện phiép tính
a)\(\dfrac{7}{4}\)+\(\dfrac{3}{2}\)+\(\dfrac{-9}{16}\)
b)\(\dfrac{-2}{7}\)+\(\dfrac{3}{5}\)+\(\dfrac{9}{7}\)+\(\dfrac{-18}{5}\)
c)\(\left\{-\dfrac{5}{13}\right\}\)+\(\dfrac{11}{10}\)-\(\dfrac{-9}{10}\)+\(\dfrac{-8}{13}\)
bài 2:tìm x biết
a)\(\dfrac{2}{9}\)-x=\(\dfrac{-5}{9}\)
b)x+\(\dfrac{-7}{13}\)=\(\dfrac{1}{2}\)
B5: Tính hợp lý:
a, \(\dfrac{11}{22}-\dfrac{3}{16}.\dfrac{8}{18}+\dfrac{1}{18}\)
b, \(\dfrac{5}{7}+\dfrac{3}{7}:4-\dfrac{8}{9}.\dfrac{-3}{4}\)
Tìm số nguyên x thỏa mãn
\(\dfrac{-9}{7}+\dfrac{5}{-7}< x\le\dfrac{-5}{2}+\dfrac{18}{4}\)
Bài 1: Thực hiện phép tính:
1) \(\dfrac{-17}{30}-\dfrac{11}{-15}+\dfrac{-7}{12}\)
2) \(\dfrac{-5}{9}+\dfrac{5}{9}:\left(1\dfrac{2}{3}-2\dfrac{1}{12}\right)\)
3) \(\dfrac{-7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}-\dfrac{18}{25}\)
Tìm x, biết:
\(a,\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(b,\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\)
\(c,\dfrac{x}{8}=\dfrac{9}{4}\)
\(d,\dfrac{x-3}{2}=\dfrac{18}{x-3}\)
\(e,4,5x-6,2x=6,12\)
\(h,11,4-\left(x-3,4\right)=-16,2\)
\(\dfrac{3}{15}.\dfrac{5}{9}:\dfrac{-18}{17}.\dfrac{14}{17}\)
\(\dfrac{12}{7}.\dfrac{7}{4}+\dfrac{35}{11}:\dfrac{245}{121}\)
giúp mình với
\(\dfrac{3}{15}.\dfrac{5}{9}:\dfrac{-18}{17}.\dfrac{14}{17}\)
\(\dfrac{12}{7}.\dfrac{7}{4}+\dfrac{35}{11}:\dfrac{245}{121}\)
giúp mình với