Question

\(\dfrac{1}{a-b}.\sqrt{3^2\left(a-b\right)^2}\) vs a>b

giúp vs

Answer 1

\(\dfrac{1}{a-b}\cdot\sqrt{3^2\left(a-b\right)^2}\left(a>b\right)\\ =\dfrac{1}{a-b}\cdot3\left|a-b\right|=\dfrac{3\left(a-b\right)}{a-b}=3\)