Question

\(\dfrac{1}{3}.\dfrac{-6}{13}.\dfrac{-9}{10}.\dfrac{-13}{36}\)

Answer 1

\(\dfrac{1}{3}\cdot\dfrac{-6}{13}\cdot\dfrac{-9}{10}\cdot\dfrac{-13}{36}\)

\(=-\dfrac{1}{3}\cdot\dfrac{9}{10}\cdot\dfrac{13}{13}\cdot\dfrac{6}{36}\)

\(=-\dfrac{3}{10}\cdot\dfrac{1}{6}=\dfrac{-1}{2\cdot10}=-\dfrac{1}{20}\)

Answer 2

\(\dfrac{1}{3}\cdot\dfrac{-6}{13}\cdot\dfrac{-9}{10}\cdot\dfrac{-13}{36}\\ =\dfrac{1\cdot\left(-6\right)\cdot\left(-9\right)\cdot\left(-13\right)}{3\cdot13\cdot10\cdot36}\\ =\dfrac{1\cdot\left(-1\right)\cdot6\cdot\left(-1\right)\cdot3\cdot3\cdot\left(-1\right)\cdot13}{3\cdot13\cdot10\cdot6\cdot3\cdot2}\\ =\dfrac{1\cdot\left(-1\right)\cdot\left(-1\right)\cdot\left(-1\right)}{10\cdot2}\\ =\dfrac{-1}{20}\)