Các câu hỏi tương tự
1. So sánh
a) \(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}+\dfrac{1}{2^{2021}}\) và B= \(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{13}{60}\)
b) \(C=\dfrac{2019}{2021}+\dfrac{2021}{2022}\) và \(D=\dfrac{2020+2022}{2019+2021}.\dfrac{3}{2}\)
\(\dfrac{2021}{2021^2+1}và\dfrac{2022}{2022^2+1}\)so sánh
Tính : S = \(1-\dfrac{1}{2}+\dfrac{1}{3}-\)\(\dfrac{1}{4}+...+\dfrac{1}{2019}-\dfrac{1}{2020}+\dfrac{1}{2021}\)và
P = \(\dfrac{1}{2011}+\dfrac{1}{2012}+\dfrac{1}{2013}+...+\dfrac{1}{2020}+\dfrac{1}{2021}\)
Tính : \(\left(S-P\right)^{2022}\)
\(B=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{2020}}+\dfrac{1}{3^{2021}}< \dfrac{1}{2}\)
so sánh:
a)C= \(\dfrac{100^{99}+1}{100^{100}+1}\) và D= \(\dfrac{100^{100}+1}{100^{101}+1}\)
b)E=\(\dfrac{2020^{2021}+1}{2020^{2022}+1}\) và F=\(\dfrac{2020^{2020}+1}{2020^{2021}+1}\)
\(\dfrac{\dfrac{2022}{1}+\dfrac{2021}{2}+\dfrac{2020}{3}+...+\dfrac{1}{2022}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2023}}\)
Giúp mình câu này với ạ
a, \(\left(2x-1\right)\left(x+\dfrac{2}{3}\right)=0\)
b, \(\dfrac{x+4}{2019}+\dfrac{x+3}{2020}=\dfrac{x+2}{2021}+\dfrac{x+1}{2022}\)
So sánh A=\(\dfrac{1}{100}+\dfrac{1}{101}+\dfrac{1}{102}+..+\dfrac{1}{2021}\)và B=20. So sánh A và B
31 tháng 3 2021 lúc 18:11
Bài 1:
a)So sánh \(\left(\dfrac{3}{4}\right)^{2021}+1với\dfrac{3}{4}+1\)
b)Cho x,y,z khác 0 thỏa mãn
\(\dfrac{2x-3}{5}=\dfrac{5y-2z}{3}=\dfrac{3z-5x}{2}\)
Tính GTBT: B=\(\dfrac{12x-5y-3z}{x-3y+2z}\)