Ta có: \(\left\{{}\begin{matrix}n_{HCl}=0,2.0,3=0,06\left(mol\right)\\n_{H_2SO_4}=0,2.0,1=0,02\left(mol\right)\end{matrix}\right.\)
PTHH:
`NaOH + HCl -> NaCl + H_2O`
`2NaOH + H_2SO_4 -> Na_2SO_4 + 2H_2O`
Theo PT: `n_{NaOH} = n_{HCl} + 2n_{H_2SO_4} = 0,1 (mol)`
`=> V_{ddNaOH} = (0,1)/1 = 0,1 (l) = 100 (ml)`