Question

c)x ² -16 =x+4

Answer 1

\(c,x^2-16-x-4=0\)

\(\left(x^2-4^2\right)-\left(x+4\right)=0\)

\(\left(x-4\right).\left(x+4\right)-\left(x+4\right)=0\)

\(\left(x+4\right).\left(x-4-1\right)=0\)

\(\Rightarrow x=-4\) hoặc \(x=5\)

Answer 2

c: =>(x+4)(x-4-1)=0

=>(x+4)(x-5)=0

=>x=5 hoặc x=-4